Page 1 of 2: PHYSIOLOGY---what is the conduction velocity of the axon????

drkbravva · Credits: 24046 My Scrapbook My Reading List 1 Books

A squid axon is placed on stimulating electrodes and an intracellular electrode
is inserted and connected through a cathode ray oscilloscope (CRO) to an indifferent
electrode.when the axon is stimulated,the latent period is 1.5ms. the intracellular electrode is 6cm from
the anode of the stimulator & 4.5 cm the cathode of the stimulator.
what is the conduction velocity of the axon????

(a) 15m/s
(b) 30m/s
(c) 40m/s
(d) 67.5m/s

can one calculate this one for as i was unable to cal. it......pls...do cell the ,method / formula/.....

BRAVO · Credits: 46105 My Scrapbook

v=distance/time

distance=4.5cm
time=1.5mS

its 30m/s,thats how i calculated....

vineetgsvm · Credits: 122793 My Scrapbook

well ur pick of the distance seems to be just right but it could have been 6 cm also...
so i try to give the reason for the same:

Cathode ray tubes emit electrons from a negatively charged metal electron emitter (the "cathode"). These are accelerated to high speeds by a voltage difference between the cathode and the positively charged anode, shaped around where the electron beam goes...

hence what i understand of the question is that the intracellular electrode is connecetd to the cathode hence shud be emitting the electron or the impulse. now shud we consider the latent period to be that of time b/w cathode and axon electrode ( i.e 4.5/1.5 =30m/s) or time to reach anode from the axon electrode?? (i.e 6/1.5=40m/s)

so kindly explain the choice of ur distance as obviously the amswer seems to be among these two choices....

any more explanations ..plz

draditithegreat · Credits: 1248020 My Scrapbook

how u guys are calculating the distance?

drkbravva · Credits: 24046 My Scrapbook My Reading List 1 Books

cathode is the stimulating electrode.
then we must consider the distance from the cathode...as in this case 4.5 cm
next the formula is as simple as velocity=distance /time
so velocity=4.5cm/1.5ms
so velocity=0.045m/0.0015s
so velocity=30m/s

correct me if i am wrong...

nutsnitin · Credits: 15174 My Scrapbook

as electrons move from cathode to anode( negative point to positive)..we will consider distance from cathode obviously....

soniadr25 · Credits: 2072 My Scrapbook

nutsnitin · Credits: 15174 My Scrapbook

hi sonia.....what do u think an electrode doing here.......its obviously generating impulse by electron movements from cathode to anode....

draditithegreat · Credits: 1248020 My Scrapbook

Definition

Nerve conduction velocity (NCV) is a test of the speed of conduction of impulses through a nerve.

How the test is performed

The nerve is stimulated, usually with surface electrodes, which are patch-like electrodes (similar to those used for ECG) placed on the skin over the nerve at various locations. One electrode stimulates the nerve with a very mild electrical impulse.

The resulting electrical activity is recorded by the other electrodes. The distance between electrodes and the time it takes for electrical impulses to travel between electrodes are used to calculate the nerve conduction velocity.Electromyography is often done at the same time as the NCV test.

hope it solves the problem....

draditithegreat · Credits: 1248020 My Scrapbook

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